Theory of Newton's rings:
2) Expression for the diameter of Newton's rings by reflected light:
Let a plano-convex lens be placed on a plane glass plate. Let R is the radius of curvature of the lens and C is the centre of curvature. The thickness of the air film at point B is MO(=t) at a distance of ON=rₙ from the point of contact O.
For interference due to reflected light,
The path difference between
two interfering rays = 2μtcos( r+ϴ ) +𝞴 /2
Here, μ= 1 (for air film)
r= 0 (for normal incidence)
Geometrical Optics and Interference
And ϴ = 0 ( for large value of R )
.•. path difference=2t + 𝞴 /2 ...(1)
From figure A) ,
R² = rₙ²+(R-t)²
rₙ²= R²-(R-t)²
rₙ²= 2Rt-t²
Since R >>t, t² becomes very small, so it can be neglected.
rₙ² = 2R.t
2t = rₙ²/R
Putting this value of 2t in eq.(1) we get,
Path difference= rₙ²/R+𝞴 /2 ....(2)
Where, rₙ = radius of the nth Newton's ring.
For dark rings:
The condition of dark ring is
Path difference = (2t+1)𝞴 /2
.•. rₙ²/R+𝞴 /2= (2n+1)𝞴 /2
.•. rₙ²/R=n𝞴
If Dₙ is the diameter of the nth Newton's rings then,
rₙ=Dₙ/2 ⇒ rₙ²=Dₙ²/4
.•. Dₙ²/4R =n𝞴 i.e. Dₙ²=4Rn𝞴
Dₙ = 2⎷nR𝞴
.•. Diameter of dark ring is the proportional to the square root of natural number
( Dₙ ∝ ⎷n)
For bright ring:
For condition for bright ring is that, path difference=n𝞴
.•. rₙ²/R + 𝞴/2=n𝞴
rₙ²/R= (2n-1)𝞴/2 where n= 1,2,3,......
Putting rₙ² = Dₙ²/4
.•. Dₙ²/4R = (2n-1) 𝞴/2
Dₙ² = 4R(2n-1) 𝞴/2
=2𝞴R(2n-1)
Dₙ = ⎷2(2n-1)𝞴R
Diameter of the bright ring is proportional to the square root of odd natural numbers.
Dₙ ∝ (2n-1)
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